使用Hibernate过滤集合元素的两种方法

List list = session.createQuery( " from Programer " ).list();
        
         for (Iterator iter = list.iterator();iter.hasNext();)
         ... {
           Programer p = (Programer)iter.next();
           Collection pcs = session.createFilter(p.getComputers(),  " where this.id>'3' " ).list();
           
            for (Iterator iter1 = pcs.iterator();iter1.hasNext();) ... {
               Computer c = (Computer)iter1.next();
               System.out.println(c.getName());
           }           
}

       < set name = " computers "  cascade = " save-update "  lazy = " true " >
             < key >
                 < column name = " programer_id "  length = " 50 "   />
             </ key >
             < one - to - many  class = " com.Computer "   />
             < filter name = " idFilter "  condition = " id>:idStr " ></ filter >
         </ set >
     </ class >
     < filter - def name = " idFilter " >
        < filter - param name = " idStr "  type = " string " />
     </ filter - def >

List list = session.createQuery( " from Programer " ).list();
        
         for (Iterator iter = list.iterator();iter.hasNext();)
         ... {
           Programer p = (Programer)iter.next();
           Filter filter = session.enableFilter( " idFilter " );
           filter.setParameter( " idStr " ,  " 3 " );
            for (Iterator iter1 = p.getComputers().iterator();iter1.hasNext();) ... {
               Computer c = (Computer)iter1.next();
               System.out.println(c.getName());
           }           
        }