python静态方法实例

系统 1499 0

本文实例讲述了python静态方法。分享给大家供大家参考。

具体实现方法如下:

复制代码 代码如下:
staticmethod Found at: __builtin__
staticmethod(function) -> method
    
    Convert a function to be a static method.
    
    A static method does not receive an implicit first argument.
    To declare a static method, use this idiom:
    
    class C:
    def f(arg1, arg2, ...): ...
    f = staticmethod(f)
    
    It can be called either on the class (e.g. C.f()) or on an
     instance
    (e.g. C().f()).  The instance is ignored except for its class.
    
    Static methods in Python are similar to those found in
     Java or C++.
    For a more advanced concept, see the classmethod builtin.

class Employee:
   """Employee class with static method isCrowded"""
 
   numberOfEmployees = 0  # number of Employees created
   maxEmployees = 10  # maximum number of comfortable employees
 
   def isCrowded():
      """Static method returns true if the employees are crowded"""
 
      return Employee.numberOfEmployees > Employee.maxEmployees
 
   # create static method
   isCrowded = staticmethod(isCrowded)
 
   def __init__(self, firstName, lastName):
      """Employee constructor, takes first name and last name"""
 
      self.first = firstName
      self.last = lastName
      Employee.numberOfEmployees += 1
 
   def __del__(self):
      """Employee destructor"""
 
      Employee.numberOfEmployees -= 1    
 
   def __str__(self):
      """String representation of Employee"""
 
      return "%s %s" % (self.first, self.last)
 
# main program
def main():
   answers = [ "No", "Yes" ]  # responses to isCrowded
   
   employeeList = []  # list of objects of class Employee
 
   # call static method using class
   print "Employees are crowded?",
   print answers[ Employee.isCrowded() ]
 
   print "\nCreating 11 objects of class Employee..."
 
   # create 11 objects of class Employee
   for i in range(11):
      employeeList.append(Employee("John", "Doe" + str(i)))
 
      # call static method using object
      print "Employees are crowded?",
      print answers[ employeeList[ i ].isCrowded() ]
 
   print "\nRemoving one employee..."
   del employeeList[ 0 ]
 
   print "Employees are crowded?", answers[ Employee.isCrowded() ]
 
if __name__ == "__main__":
   main()

希望本文所述对大家的Python程序设计有所帮助。


更多文章、技术交流、商务合作、联系博主

微信扫码或搜索:z360901061

微信扫一扫加我为好友

QQ号联系: 360901061

您的支持是博主写作最大的动力,如果您喜欢我的文章,感觉我的文章对您有帮助,请用微信扫描下面二维码支持博主2元、5元、10元、20元等您想捐的金额吧,狠狠点击下面给点支持吧,站长非常感激您!手机微信长按不能支付解决办法:请将微信支付二维码保存到相册,切换到微信,然后点击微信右上角扫一扫功能,选择支付二维码完成支付。

【本文对您有帮助就好】

您的支持是博主写作最大的动力,如果您喜欢我的文章,感觉我的文章对您有帮助,请用微信扫描上面二维码支持博主2元、5元、10元、自定义金额等您想捐的金额吧,站长会非常 感谢您的哦!!!

发表我的评论
最新评论 总共0条评论