杭电2122--Ice_cream's world III

系统 2017 0

Ice_cream’s world III

                                                   Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
                                                                               Total Submission(s): 1146    Accepted Submission(s): 379


Problem Description
ice_cream’s world becomes stronger and stronger; every road is built as undirected. The queen enjoys traveling around her world; the queen’s requirement is like II problem, beautifies the roads, by which there are some ways from every city to the capital. The project’s cost should be as less as better.
 

Input
Every case have two integers N and M (N<=1000, M<=10000) meaning N cities and M roads, the cities numbered 0…N-1, following N lines, each line contain three integers S, T and C, meaning S connected with T have a road will cost C.
 

Output
If Wiskey can’t satisfy the queen’s requirement, you must be output “impossible”, otherwise, print the minimum cost in this project. After every case print one blank.
 

Sample Input
2 1
0 1 10
 
4 0
 

Sample Output
10
impossible
 

Author
Wiskey
 

Source
 

Recommend
威士忌   |   We have carefully selected several similar problems for you:   2121   2119   2129   2118   2117  
 
//并查集实现克鲁斯卡尔;
        
           1
        
         #include <stdio.h>


        
           2
        
         #include <algorithm>


        
           3
        
        
          using
        
        
          namespace
        
        
           std;


        
        
           4
        
        
          int
        
         father[
        
          1010
        
        
          ] ;


        
        
           5
        
        
           6
        
        
          struct
        
        
           rode


        
        
           7
        
        
          {


        
        
           8
        
        
          int
        
        
           a, b ,c;


        
        
           9
        
        
          };


        
        
          10
        
         rode num[
        
          10010
        
        
          ];


        
        
          11
        
        
          12
        
        
          bool
        
        
           cmp(rode a, rode b)


        
        
          13
        
        
          {


        
        
          14
        
        
          return
        
         a.c <
        
           b.c ;


        
        
          15
        
        
          }


        
        
          16
        
        
          17
        
        
          int
        
         find(
        
          int
        
        
           a)


        
        
          18
        
        
          {


        
        
          19
        
        
          while
        
        (a !=
        
           father[a])


        
        
          20
        
             a =
        
           father[a];


        
        
          21
        
        
          return
        
        
           a;


        
        
          22
        
        
          }


        
        
          23
        
        
          24
        
        
          void
        
         mercy(
        
          int
        
         a, 
        
          int
        
        
           b)


        
        
          25
        
        
          {


        
        
          26
        
        
          int
        
         q =
        
           find(a);


        
        
          27
        
        
          int
        
         p =
        
           find(b);


        
        
          28
        
        
          if
        
        (q !=
        
           p)


        
        
          29
        
             father[q] =
        
           p;


        
        
          30
        
        
          31
        
        
          }


        
        
          32
        
        
          33
        
        
          int
        
        
           main()


        
        
          34
        
        
          {


        
        
          35
        
        
          int
        
        
           i, n, m;


        
        
          36
        
        
          while
        
        (~scanf(
        
          "
        
        
          %d %d
        
        
          "
        
        , &n, &
        
          m))


        
        
          37
        
        
              {


        
        
          38
        
        
          for
        
        (i=
        
          0
        
        ; i<n; i++
        
          )


        
        
          39
        
                 father[i] =
        
           i;


        
        
          40
        
        
          for
        
        (i=
        
          0
        
        ; i<m; i++
        
          )


        
        
          41
        
                 scanf(
        
          "
        
        
          %d %d %d
        
        
          "
        
        ,&num[i].a, &num[i].b, &
        
          num[i].c);


        
        
          42
        
                 sort(num, num+
        
          m, cmp);


        
        
          43
        
        
          int
        
         total = 
        
          0
        
        
          ;


        
        
          44
        
        
          for
        
        (i=
        
          0
        
        ; i<m; i++
        
          )


        
        
          45
        
        
                  {


        
        
          46
        
        
          //
        
        
          mercy(num[i].a, num[i].b);
        
        
          47
        
        
          if
        
        (find(num[i].a) ==
        
           find(num[i].b))


        
        
          48
        
        
          continue
        
        
          ;


        
        
          49
        
        
          else
        
        
          50
        
        
                      {


        
        
          51
        
        
          //
        
        
          printf("1\n");
        
        
          52
        
                         total +=
        
           num[i].c;


        
        
          53
        
        
                          mercy(num[i].a, num[i].b) ;


        
        
          54
        
        
                      }    


        
        
          55
        
        
                  }


        
        
          56
        
        
          int
        
         ac = 
        
          0
        
        
          ;


        
        
          57
        
        
          for
        
        (i=
        
          0
        
        ; i<n; i++
        
          )


        
        
          58
        
        
                  {


        
        
          59
        
        
          if
        
        (father[i] ==
        
           i)


        
        
          60
        
                     ac++
        
          ;


        
        
          61
        
        
                  }


        
        
          62
        
        
          if
        
        (ac == 
        
          1
        
        
          )


        
        
          63
        
                 printf(
        
          "
        
        
          %d\n\n
        
        
          "
        
        
          , total);


        
        
          64
        
        
          else
        
        
          65
        
                 printf(
        
          "
        
        
          impossible\n\n
        
        
          "
        
        
          );


        
        
          66
        
        
              }


        
        
          67
        
         }
      

 

 

杭电2122--Ice_cream's world III


更多文章、技术交流、商务合作、联系博主

微信扫码或搜索:z360901061

微信扫一扫加我为好友

QQ号联系: 360901061

您的支持是博主写作最大的动力,如果您喜欢我的文章,感觉我的文章对您有帮助,请用微信扫描下面二维码支持博主2元、5元、10元、20元等您想捐的金额吧,狠狠点击下面给点支持吧,站长非常感激您!手机微信长按不能支付解决办法:请将微信支付二维码保存到相册,切换到微信,然后点击微信右上角扫一扫功能,选择支付二维码完成支付。

【本文对您有帮助就好】

您的支持是博主写作最大的动力,如果您喜欢我的文章,感觉我的文章对您有帮助,请用微信扫描上面二维码支持博主2元、5元、10元、自定义金额等您想捐的金额吧,站长会非常 感谢您的哦!!!

发表我的评论
最新评论 总共0条评论