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以一种"廉价"的方式获取页面的标题(downmoon)

有朋友问到：“我需要得到一个webpage的title，因为这个title一般都比较靠前，只要取得html的前面少量内容就可以了。因为要取得很多个页面的title,如果下载整个htmlcode，肯定比较浪费时间。.net好像没有现成的类可以干这件事情(取得部分html)，我应该如何去实现？”一种比较"廉价"(即较小成本条件下)的解决思路：第一步：取出含有页面title部分的最小集合。这是“廉价”的关键！第二步：用正则表达式取出和</title</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:21:16</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3016</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/14208" title="Netty系列之Netty安全性" target="_blank" onclick="return recordId('',)">Netty系列之Netty安全性 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/14208" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/12.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/14208';}else{window.open('/article/14208');}" style="cursor: pointer;">1.背景1.1.严峻的安全形势1.1.1.OpenSSLHeartbleed漏洞2014年上半年对网络安全影响最大的问题就是OpenSSLHeartbleed漏洞，来自Codenomicon和谷歌安全部门的研究人员发现OpenSSL的源代码中存在一个漏洞，可以让攻击者获得服务器上64K内存中的数据内容。该漏洞在国内被译为”OpenSSL心脏出血漏洞”，因其破坏性之大和影响的范围之广，堪称网络安全里程碑事件。OpenSSL是为网络通信提供安全及数据完整性的一</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:13:09</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3016</span></span>  </p> </article><article class="excerpt"> <header> <a title="数据库相关" class="label label-important zj-del-target" href="/category/32">数据库相关<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/8293" title="uva 10051 Tower of Cubes(DAG最长路）" target="_blank" onclick="return recordId('',)">uva 10051 Tower of Cubes(DAG最长路） </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/8293" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/2.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/8293';}else{window.open('/article/8293');}" style="cursor: pointer;">题目连接：10051-TowerofCubes题目大意：有n个正方体，从序号1~n，对应的每个立方体的6个面分别有它的颜色（用数字给出），现在想要将立方体堆成塔，并且上面的立方体的序号要小于下面立方体的序号，相邻的面颜色必须相同。输出最高值和路径。解题思路：因为立方体可以旋转，所以一个序号的立方体对应这6种不同的摆放方式，可以将问题理解成DAG最长路问题，只是搜索范围是从i+1开始到n。然后记录路径要开两个2维数组。路径不唯一，随便输出一条。#includ</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 01:55:00</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3016</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/19270" title="[转]分布式数据库概述" target="_blank" onclick="return recordId('',)">[转]分布式数据库概述 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/19270" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/19.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/19270';}else{window.open('/article/19270');}" style="cursor: pointer;">From:http://fineboy.cnblogs.com/archive/2005/08/03/206395.html1．前言随着传统的数据库技术日趋成熟、计算机网络技术的飞速发展和应用范围的扩充，数据库应用已经普遍建立于计算机网络之上。这时集中式数据库系统表现出它的不足：数据按实际需要已在网络上分布存储，再采用集中式处理，势必造成通信开销大；应用程序集中在一台计算机上运行，一旦该计算机发生故障，则整个系统受到影响，可靠性不高；集中式处理引起系统的规</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 23:17:18</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3015</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/18633" title="查找串t在串s中出现的次数" target="_blank" onclick="return recordId('',)">查找串t在串s中出现的次数 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/18633" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/9.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/18633';}else{window.open('/article/18633');}" style="cursor: pointer;">//查找串t在串s中出现的次数，模式匹配，KMP算法#include<iostream>#include<string>#include<vector>usingnamespacestd;strings,t;vector<int>next;voidnextIt()...{inti=0,j=-1,n=t.size();next[0]=-1;while(i<n)...{if(j==-1||t[i]==t[j])...{i++;j++;next[i]=j;}el</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 23:09:00</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3015</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/11084" title="MapReduce 模式、算法和用例" target="_blank" onclick="return recordId('',)">MapReduce 模式、算法和用例 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/11084" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/13.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/11084';}else{window.open('/article/11084');}" style="cursor: pointer;">本文译自MapreducePatterns,Algorithms,andUseCases在这篇文章里总结了几种网上或者论文中常见的MapReduce模式和算法，并系统化的解释了这些技术的不同之处。所有描述性的文字和代码都使用了标准hadoop的MapReduce模型，包括Mappers,Reduces,Combiners,Partitioners,和sorting。如下图所示。基本MapReduce模式计数与求和问题陈述:有许多文档，每个文档都有一些字段组</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:29:31</span></span> 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