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ext中ComboBox+Ajax+分页联动代码和注释

今天花了1下午时间研究出了ComboBox+Ajax+分页联动效果.ext学习初步见效下面代码直接就能运行,用list模拟了数据库中取数据以下是目录结构以下是代码test1.jsp<%@pagelanguage="java"import="java.util.*"pageEncoding="UTF-8"%></span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:28:19</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/14612" title="关于ListView中加入并选取checkbox错位的问题" target="_blank" onclick="return recordId('',)">关于ListView中加入并选取checkbox错位的问题 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/14612" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/4.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/14612';}else{window.open('/article/14612');}" style="cursor: pointer;">在ListView中的列表项中定义checkbox是一个常见手法，不过如果在listview使用了ViewHolder缓存的话就会遇到一个很恶心的问题，就是列表项错位的问题，为此我想到了一个自认为还算简单的解决方法，就是在自定义Adapter时加入checkbox.setTag(position)这样一句代码。这里checkbox为当前列表项的复选框，position为当前列表项位置。然后为checkbox设置点击事件，checkbox.setOnClic</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:18:01</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/13314" title="汉诺塔递归解法" target="_blank" onclick="return recordId('',)">汉诺塔递归解法 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/13314" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/16.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/13314';}else{window.open('/article/13314');}" style="cursor: pointer;">汉诺塔的递归算法假设有3个分别命名为X、Y和Z的塔座，在塔座X上插有n个直径大小各不相同、依小到大编号为1、2…n的圆盘。现要求将X轴上的n个圆盘移至塔座Z上并仍按同样顺序叠排，圆盘移动时必须遵守下列规则：1、每次只能移动一个圆盘；2、圆盘可以插在X、Y和Z中任一塔座上；3、任何时刻都不能将一个较大的圆盘压在较小的圆盘之上。递归算法的思路：当n=1时，问题比较简单，只要将编号为1的圆盘从塔座X直接移至塔座Z上即可。当n>1时，需利用塔座Y作辅助塔座，若能设</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:02:00</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/12750" title="IP地址规划的重要性" target="_blank" onclick="return recordId('',)">IP地址规划的重要性 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/12750" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/8.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/12750';}else{window.open('/article/12750');}" style="cursor: pointer;">在搭建一个局域网的时候，IP地址规划的意义重大。如果你的网络永远不会被扩展和定制，那么你可以随意的规划IP地址，只要能保证路由是通的就可以了。然而如果将来有一天你需要对已有的网络进行拓展，那么就需要精心安排地址了。原则就是：尽量使逻辑上同类的地址规划成连续的地址，并且起始地址最好是2的次幂。这样做的原因在于可以方便的划分子网。考虑下面的拓扑：有一天，需要在该局域网增加一台加密网关，所有到达外部网络2的流量都要被加密，而且需要把加密流量路由指向加密网关(流量</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:30:33</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/12156" title="二叉树遍历--递归实现" target="_blank" onclick="return recordId('',)">二叉树遍历--递归实现 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/12156" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/14.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/12156';}else{window.open('/article/12156');}" style="cursor: pointer;">递归这东西真是抽象，我看着看着算法，就囫囵吞枣地的写了下，写得囧了···这次先用递归实现先序，中序，后序遍历算法。先大概说下原理：我输入一大串字符，中间#就是代表了空，基本的储存结构就是二叉链表。主要就是二叉树的创建和三种顺序的遍历。二叉树的创建通过从左孩子开始创建不断递归，知道读取了#，开始创建对应的右孩子，继续递归。访问的时候对于三种顺序不过就是对于操作的顺序改变而已。对于下面的程序，按照图里面的二叉树建立方式：输入ABD#G###CE##FH###就</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:30:11</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/12055" title="呼拉拉一片陈一舟和王兴PK声" target="_blank" onclick="return recordId('',)">呼拉拉一片陈一舟和王兴PK声 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/12055" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/14.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/12055';}else{window.open('/article/12055');}" style="cursor: pointer;"><iframealign="center"marginwidth="0"marginheight="0"src="http://www.zealware.com/csdnblog336280.html"frameborder="0"width="336"scrolling="no"height="280"></iframe>昨天怎么了，玩聚算出来呼拉拉一片博文、新闻都是陈一舟和王兴PK，看了半天这个玩聚热点故事才知道事情的来龙去脉。之前，老是从各种小道bl</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:30:07</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/11524" title="2011年06月09日Google涂鸦-吉他-源代码" target="_blank" onclick="return recordId('',)">2011年06月09日Google涂鸦-吉他-源代码 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/11524" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/13.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/11524';}else{window.open('/article/11524');}" style="cursor: pointer;">注意：本地使用会由于Flash安全设置而无法发声，上传到WEB服务器后一切正常，通过IE/FF/Chrome测试。源码：见附件转载：http://www.oschina.net/news/18728/google-index-doodle-source-code2011年06月09日Google涂鸦-吉他-源代码</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:29:48</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><article class="excerpt"> <header> <a title="各行各业" class="label label-important zj-del-target" href="/category/38">各行各业<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/9342" title="casperjs进行web功能自动化测试demo" target="_blank" onclick="return recordId('',)">casperjs进行web功能自动化测试demo </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/9342" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/2.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/9342';}else{window.open('/article/9342');}" style="cursor: pointer;">通过一周多的学习和总结，终于掌握了casperjs用于自动化的方法，填平了大大小小的各种坑。casperjs是一个新兴的测试框架，网上资料很少，基本上靠翻译英文资料。贡献出来，供大家参考：//page.js，存放页面元素//c表示通过css选择元素，x表示通过xpath选择元素varbaseurl="http://www.cnblogs.com/reach296/";varbase={//首页url:baseurl,c:{登录表单:'form#login'</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:26:51</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2175</span></span>  </p> </article><div class="pagination" style="display:;"> <ul><li><a href="/search/java/1/p/1">首页</a></li> <li class="prev-page"><a href="/search/java/1/p/2470">上一页</a></li> <li><a href="/search/java/1/p/2469">2469</a></li><li><a href="/search/java/1/p/2470">2470</a></li><li class="active"><span>2471</span></li><li><a href="/search/java/1/p/2472">2472</a></li><li><a href="/search/java/1/p/2473">2473</a></li> <li class="next-page"><a href="/search/java/1/p/2472">下一页</a></li> <li><a href="/search/java/1/p/2924">末页</a></li> <li><span>共 2924页,共29234条</span></li> </ul> </div> </div> </div>   <style type="text/css"> .d_postlist .text { /* height: 30px; */ display: block; /* height: 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