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完整的简单层拖动代码

howtomakeadragdivision-<ahref="http://www.never-online.net"target="_blank"><ahref="http://www.never-online.net"target="_blank">http://www.never-online.net<</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 23:27:10</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2007</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/19489" title="几个好用eclipse插件（更新、下载地址）" target="_blank" onclick="return recordId('',)">几个好用eclipse插件（更新、下载地址） </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/19489" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/6.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/19489';}else{window.open('/article/19489');}" style="cursor: pointer;">Freemarker:在线更新http://www.freemarker.org/eclipse/update/插件下载http://www.jboss.org/tools/download/Struts2:在线更新http://mvcwebproject.sourceforge.net/update/插件下载http://sourceforge.net/projects/mvcwebproject/files/Propedit:在线更新http://pr</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 23:20:09</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2007</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/17786" title="多条件进行查询" target="_blank" onclick="return recordId('',)">多条件进行查询 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/17786" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/1.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/17786';}else{window.open('/article/17786');}" style="cursor: pointer;">StringBufferbuf=newStringBuffer();buf.append("fromServicelistasslwhere1=1andsl.visValid='y'");if(vcustomerId!=null&&!vcustomerId.equals("")&&!vcustomerId.equals("null")){buf.append("andsl.vcustomerIdlike'%"+vcustomerId+"%'");}if(v</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:58:03</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2007</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/15838" title="Rational Rose和UML可视化建模基础" target="_blank" onclick="return recordId('',)">Rational Rose和UML可视化建模基础 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/15838" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/15.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/15838';}else{window.open('/article/15838');}" style="cursor: pointer;">为了成功地开发一个项目，你需要正确的过程、工具和符号（注释）。在本文中作者解释了UML是如何为你提供符号、Rational统一流程（UnifiedProcess）是如何为你提供正确的流程，以及RationalRose是如何为你提供使项目成功的工具的。什么是可视化建模？可视化建模（VISUALMODELING）是利用围绕现实想法组织模型的一种思考问题的方法。模型对于了解问题、与项目相关的每个人（客户、行业专家、分析师、设计者等）沟通、模仿企业流程、准备文档、</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:33:38</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2007</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/15403" title="zoj 1789 The Suspects" target="_blank" onclick="return recordId('',)">zoj 1789 The Suspects </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/15403" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/14.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/15403';}else{window.open('/article/15403');}" style="cursor: pointer;">这道题是并查集的题，写过这道题之后，我明白了一点，就是从根上改变所属father域<spanstyle="font-size:18px;">#include<stdio.h>#include<stdlib.h>#include<string.h>#include<math.h>intp[30000+100];inta[30000+100];intfind(intx){if(p[x]==x)returnx;p[x]=find(p[x]);returnp[x]</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:28:15</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2007</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/15401" title="zoj 1889 Ones" target="_blank" onclick="return recordId('',)">zoj 1889 Ones </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/15401" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/10.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/15401';}else{window.open('/article/15401');}" style="cursor: pointer;">这道题开始看不懂题，英文学得不好，主要是当输入为9999时要输出36位的数，这个数很难保存到一个longlong型的变量中，所以考虑取模公式，还算是一道简单题吧，不过这上午半天就做了这一道题，难受<spanstyle="font-size:18px;">#include<stdio.h>#include<stdlib.h>#include<string.h>#include<math.h>intmain(){intm,count;longlongn;whi</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:28:14</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2007</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/13759" title="SwipeView 类似桌面的滑动界面" target="_blank" onclick="return recordId('',)">SwipeView 类似桌面的滑动界面 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/13759" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/14.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/13759';}else{window.open('/article/13759');}" style="cursor: pointer;">使用了android2.0以上的ExifInterface来生成缩略图。可用来设计游戏的选关界面。importuk.co.jasonfry.android.tools.ui.PageControl.OnPageControlClickListener;importandroid.content.Context;importandroid.graphics.Rect;importandroid.util.AttributeSet;importandroid.</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:07:43</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2007</span></span>  </p> </article><div class="pagination" style="display:;"> <ul><li><a href="/search/java/1/p/1">首页</a></li> <li class="prev-page"><a href="/search/java/1/p/2837">上一页</a></li> <li><a href="/search/java/1/p/2836">2836</a></li><li><a href="/search/java/1/p/2837">2837</a></li><li class="active"><span>2838</span></li><li><a href="/search/java/1/p/2839">2839</a></li><li><a href="/search/java/1/p/2840">2840</a></li> <li class="next-page"><a 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