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安装Ubuntu 11.04 后的20件事

4.28日，Ubuntu11.04就发布了！本文将向你介绍Ubuntu11.04安装后快速配置需要做的20件事。1、不喜欢Unity？切换到Ubuntugnome经典桌面！注销unity桌面环境，然后选择登录环境为“经典桌面”即可进入。若是你喜欢Unity，可是你的显卡不给力3D不支持，怎么办呢？安装Unity-2D：引用sudoapt-add-pparepository:unity-2d-team/unity-2d-dailysudoapt-getupd

系统 2019-08-29 22:05:20 3003

编程技术

第四章 Controller接口控制器详解（4）——跟

4.12、ParameterizableViewController参数化视图控制器，不进行功能处理（即静态视图），根据参数的逻辑视图名直接选择需要展示的视图。Java代码

系统 2019-08-29 22:00:17 3003

Oracle

Oracle很实用的汇总报表实现方式！grouping_id

在财务系统或者其他报表统计的功能里我想类似下面这张报表的case很多，有了grouping_id函数之后会轻松easy实现，不菲催费之力序号项目上年本年增减日均余额成本率日均余额成本率日均余额成本率总计一银行借款1用于商业票据额度国家开发银行2其它授信额度国家开发银行美国银行二集团拆入三总部拆入解析：此表是三级汇总，银行汇总到额度（商业额度、其他额度），各种额度汇总到拆入方式（银行借款、集团拆入、总部拆入）、拆入方式汇总总计。grouping_id可以实现

系统 2019-08-12 01:55:09 3003

Python

python批量处理word中的表格

defword_table_formater():fromwin32comimportclientword=client.Dispatch('Word.Application')doc=word.Documents.Open('C:\\Users\\Administrator\\Desktop\\test.docx')i=1fortableindoc.Tables:print(i,len(doc.Tables))#设置列宽table.Columns(1).

系统 2019-09-27 17:45:49 3002

编程技术

unix 计数器disk traffic含义补充

LoadRunnerController菜单tools–>options中我们可以看到是3秒钟采集一次服务器的资源信息，如下图所示：这就等价于以下命令：iostat–d3n输出的tps或者iostat–x3中的r/s+w/siostat–d3n的输出类似如下：#iostat-d3nLinux2.6.18-194.el5(www2.×××.cn)01/23/2011_x86_64_(8CPU)Device:tpsBlk_read/sBlk_wrtn/sBlk

系统 2019-08-29 23:32:50 3002

ASP.NET

关于进行Asp.net窗体验证的过程说明

开发asp.net程序时最常用的验证模式就是基于窗体的身份验证模式，结合global.asa和webconfig可以快速实现此种机制。笼统的说，该过程是先建一个文件夹，然后把要保护的页面放进去，接着设置一下web,config，这样就完成了保护。如果你要访问这个文件夹，就会被强制转到预先设定的登录页面，你填上正确的用户名和密码，提交，系统验证后，就把你的登陆信息写到cookie里面，这样你再去访问那个文件夹，就可以进去了，因为你的登陆凭证已经保存到cook

系统 2019-08-29 22:35:39 3002

编程技术

Contribute some useful custom control: XList

InmyVCMFCdevelopexpericence,IalwaysfindthatitisreallypooroftheCtrlsthatmicrosoftprovided,butwehavenomuchprojectbudgettobugabeautifulthird-ctrl.SosometimesweneeddosomeworktomodifythestandardControl.Forthepurposeofreuse,Ihavemylibra

系统 2019-08-29 22:24:43 3002

编程技术

以一种"廉价"的方式获取页面的标题(downmoon)

有朋友问到：“我需要得到一个webpage的title，因为这个title一般都比较靠前，只要取得html的前面少量内容就可以了。因为要取得很多个页面的title,如果下载整个htmlcode，肯定比较浪费时间。.net好像没有现成的类可以干这件事情(取得部分html)，我应该如何去实现？”一种比较"廉价"(即较小成本条件下)的解决思路：第一步：取出含有页面title部分的最小集合。这是“廉价”的关键！第二步：用正则表达式取出和</title</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:21:16</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3002</span></span>  </p> </article><article class="excerpt"> <header> <a title="Linux" class="label label-important zj-del-target" href="/category/53">Linux<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/9493" title="linux下安装memcache" target="_blank" onclick="return recordId('',)">linux下安装memcache </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/9493" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/1.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/9493';}else{window.open('/article/9493');}" style="cursor: pointer;">首先的下软件libevent:http://libevent.org/memcached:http://memcached.org/我的文件名是：libevent-2.0.22-stable.tar.gzmemcached-1.4.24.tar.gz1）.memcached依赖libevent文件，所以必须得先安装libevent。解压：tarzxvflibevent-2.0.22-stable.tar.gz预编译：./configure--prefix=</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:26:55</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3002</span></span>  </p> </article><article class="excerpt"> <header> <a title="数据库相关" class="label label-important zj-del-target" href="/category/32">数据库相关<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/8293" title="uva 10051 Tower of Cubes(DAG最长路）" target="_blank" onclick="return recordId('',)">uva 10051 Tower of Cubes(DAG最长路） </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/8293" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/12.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/8293';}else{window.open('/article/8293');}" style="cursor: pointer;">题目连接：10051-TowerofCubes题目大意：有n个正方体，从序号1~n，对应的每个立方体的6个面分别有它的颜色（用数字给出），现在想要将立方体堆成塔，并且上面的立方体的序号要小于下面立方体的序号，相邻的面颜色必须相同。输出最高值和路径。解题思路：因为立方体可以旋转，所以一个序号的立方体对应这6种不同的摆放方式，可以将问题理解成DAG最长路问题，只是搜索范围是从i+1开始到n。然后记录路径要开两个2维数组。路径不唯一，随便输出一条。#includ</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 01:55:00</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">3002</span></span>  </p> </article><div class="pagination" style="display:;"> <ul><li><a href="/search/oom/1/p/1">首页</a></li> <li class="prev-page"><a href="/search/oom/1/p/415">上一页</a></li> <li><a href="/search/oom/1/p/414">414</a></li><li><a href="/search/oom/1/p/415">415</a></li><li class="active"><span>416</span></li><li><a href="/search/oom/1/p/417">417</a></li><li><a href="/search/oom/1/p/418">418</a></li> <li class="next-page"><a href="/search/oom/1/p/417">下一页</a></li> <li><a href="/search/oom/1/p/2924">末页</a></li> <li><span>共 2924页,共29234条</span></li> </ul> </div> </div> </div>   <style type="text/css"> .d_postlist .text { /* height: 30px; */ display: block; /* height: 100%; */ font-size:14px !important; width:85%; } .zj-dynamic-info li{ margin: 10px 3px; } .zj-dynamic-info .zj-a{ color: blue; cursor: pointer; } </style> <aside class="sidebar"> <div class="widget d_postlist"> <div 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