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仿iPhone开关式按钮(jQuery+CSS3)viewsourceprint?001002003004005006仿iPhone开关式按钮(jQuery+CSS3)</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:11:15</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2655</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/13990" title="/etc/rc.d/init.d 和 /etc/rc.d目录介绍" target="_blank" onclick="return recordId('',)">/etc/rc.d/init.d 和 /etc/rc.d目录介绍 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/13990" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/15.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/13990';}else{window.open('/article/13990');}" style="cursor: pointer;">本文包括3部分内容1、Linux的引导过程2、运行级别3、/etc/rc.d/与/etc/rc.d/init.d的关系“/etc/rc.d/init.d/目录下的脚本就类似与windows中的注册表，在系统启动的时候某些指定脚本将被执行”。在进入init.d之前，我们一起来做两个准备工作，linux的引导过程和运行级别的概念。一、Linux的引导过程系统启动之后，在进入init.d之前，我们先来看看系统都做了什么工作，先看看一个图从这个图中，我们从比较高的</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:10:29</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2655</span></span>  </p> </article><article class="excerpt"> <header> <a title="Java" class="label label-important zj-del-target" href="/category/41">Java<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/13283" title="java （冒泡、选择、插入）排序" target="_blank" onclick="return recordId('',)">java （冒泡、选择、插入）排序 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/13283" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/17.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/13283';}else{window.open('/article/13283');}" style="cursor: pointer;">1、冒泡排序BubbleSort最简单的排序方法是冒泡排序方法。这种方法的基本思想是，将待排序的元素看作是竖着排列的“气泡”，较小的元素比较轻，从而要往上浮。在冒泡排序算法中我们要对这个“气泡”序列处理若干遍。所谓一遍处理，就是自底向上检查一遍这个序列，并时刻注意两个相邻的元素的顺序是否正确。如果发现两个相邻元素的顺序不对，即“轻”的元素在下面，就交换它们的位置。显然，处理一遍之后，“最轻”的元素就浮到了最高位置；处理二遍之后，“次轻”的元素就浮到了次高位</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-29 22:01:31</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2655</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/12629" title="备份,是一种态度" target="_blank" onclick="return recordId('',)">备份,是一种态度 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/12629" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/19.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/12629';}else{window.open('/article/12629');}" style="cursor: pointer;">好了，前几天我们说了关于系统分区的问题，算是装双系统或是装系统的第一步，今天我们谈谈电脑的备份问题，都是个人见解，有不对的地方望大家提出来，相互学习。(有关系统分区问题参考：http://151451325.blog.163.com/blog/static/175045442012945844225/）话说电脑备份是一件很简单但是大部分人都不会去做的事，一个好的备份习惯会给你带来很多便利，像米老师，一个U盘里面的数据有N个备份，存放在各种地方，前几天把U盘</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:30:28</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2655</span></span>  </p> </article><article class="excerpt"> <header> <a title="编程技术" class="label label-important zj-del-target" href="/category/30">编程技术<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/12465" title="微软安全新闻聚焦-双周刊第十七期" target="_blank" onclick="return recordId('',)">微软安全新闻聚焦-双周刊第十七期 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/12465" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/6.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/12465';}else{window.open('/article/12465');}" style="cursor: pointer;">BiweeklySpotlights====2012.6.25–2012.7.19第17期====微软云计算的安全、可信和保障2012年6月25日如何从安全层面考量云计算解决方案？这是对云计算跃跃欲试的用户很关注的话题。云安全联盟为此推出了一项评估机制，把云计算的安全性、可信性和保障性的评估文档化，形成公开的评估登记表，简称STAR（Security,Trust&AssuranceRegistry），云计算服务提供商都可依据STAR来进行自我评估并对外公布</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:30:22</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2655</span></span>  </p> </article><article class="excerpt"> <header> <a title="Tomcat" class="label label-important zj-del-target" href="/category/50">Tomcat<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/10300" title="tomcat6中文乱码设置" target="_blank" onclick="return recordId('',)">tomcat6中文乱码设置 </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/10300" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/3.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/10300';}else{window.open('/article/10300');}" style="cursor: pointer;">get方式的解决办法：打开server.xml文件，找到区块：<Connectorport="8080"maxThreads="150"minSpareThreads="25"maxSpareThreads="75"enableLookups="false"redirectPort="8443"acceptCount="100"debug="0"connectionTimeout="20000"disableUploadTimeout="true"URIE</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 09:27:22</span></span> <span class="muted"><i class="fa fa-eye"></i><span class="zj-icon-text">2655</span></span>  </p> </article><article class="excerpt"> <header> <a title="数据库相关" class="label label-important zj-del-target" href="/category/32">数据库相关<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/6491" title="poj 1019 Number Sequence" target="_blank" onclick="return recordId('',)">poj 1019 Number Sequence </a> </h2> </header> <div class="focus"> <a class="zj-del-target" href="/article/6491" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/18.jpg" alt="" title=""></a> </div> <span class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/6491';}else{window.open('/article/6491');}" style="cursor: pointer;">http://poj.org/problem?id=1019题意：112123123412345一窜数字求第n位的数字是什么分析：拿到题就是不会。。。看了题解a[i]计算i数字的位数，s[i]计算到达i数字的总位数i数字的位数log10（i）+1#include<stdio.h>#include<math.h>constintMAXN=40000;longlonga[MAXN];longlongs[MAXN];voidinit(){s[1]=a[1]=1;</span> <p class="auth-span"> <span class="muted"><i class="fa fa-user"></i><span class="zj-icon-text">系统</span></span> <span class="muted"><i class="fa fa-clock-o"></i><span class="zj-icon-text">2019-08-12 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