原文链接： https://blog.csdn.net/jidushanzhu/article/details/81476548
python3
C = [('e', 4, 2), ('a', 2, 1), ('c', 5, 4), ('b', 3, 3), ('d', 1, 5)]
print(sorted(C, key=lambda y: y[0]))
#输出[('a', 2, 1), ('b', 3, 3), ('c', 5, 4), ('d', 1, 5), ('e', 4, 2)]
print(sorted(C, key=lambda x: x[0]))
#[('a', 2, 1), ('b', 3, 3), ('c', 5, 4), ('d', 1, 5), ('e', 4, 2)]
print(sorted(C, key=lambda x: x[2]))
[('a', 2, 1), ('e', 4, 2), ('b', 3, 3), ('c', 5, 4), ('d', 1, 5)]
key=lambda 元素: 元素[字段索引]
比如 print(sorted(C, key=lambda x: x[2]))
x:x[]字母可以随意修改，排序方式按照中括号[]里面的维度进行排序，[0]按照第一维排序，[2]按照第三维排序
