| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 57382 | Accepted: 26983 |
本题是北大oJ上比较水的题目，在给的说明中已经把规律讲明，所以只管写代码即可
可行代码：
1
#include
<
stdio.h
>
2
int
main()
3
{
4
double
a,s;
5
int
n;
6
while
(scanf(
"
%lf
"
,
&
a)
!=
EOF)
7
{
8
n
=
0
;s
=
0
;
9
if
(a
==
0.00
)
10
break
;
11
while
(s
<
a)
12
{
13
n
++
;
14
s
+=
1.0
/
(n
+
1
);
15
}
16
printf(
"
%d card(s)\n
"
,n);
17
}
18
return
0
;
19
}
20
