http://poj.org/problem?id=1905
#include<iostream>
#include<string>
#include<cstring>
#include<cmath>
#include<cstdio>
#include<algorithm>
using namespace std;
const double K=1e-10;
const double PI=acos(-1);
int main()
{
double L,n,C;
while(cin>>L>>n>>C)
{
if(L<0&&n<0&&C<0)
break;
double L1=(1+n*C)*L;
double high=PI;
double low=0;
double mid=(high+low)/2;
while(high-low>K)
{
//cout<<(mid/2)<<" "<<sin(mid/2)<<endl;
//cout<<L1<<" "<<(mid*(L/2*asin(mid/2)))<<endl;
if(L1-(mid*(L/2/sin(mid/2)))>=K)
{
low=mid;
}
else
{
high=mid;
}
mid=(high+low)/2;
}
//cout<<mid<<endl;
printf("%.3f\n",(L/2/sin(mid/2)-L/2/tan(mid/2)));
}
return 0;
}