1 、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断
select * from people
where peopleId in ( select peopleId from people group by peopleId having count (peopleId) > 1 )
2 、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录
delete from people
where peopleId in ( select peopleId from people group by peopleId having count (peopleId) > 1 )
and rowid not in ( select min (rowid) from people group by peopleId having count (peopleId ) > 1 )
3 、查找表中多余的重复记录（多个字段）
select * from vitae a
where (a.peopleId,a.seq) in ( select peopleId,seq from vitae group by peopleId,seq having
count ( * ) > 1 )
4 、删除表中多余的重复记录（多个字段），只留有rowid最小的记录
delete from vitae a
where (a.peopleId,a.seq) in ( select peopleId,seq from vitae group by peopleId,seq having count ( * ) > 1 )
and rowid not in ( select min (rowid) from vitae group by peopleId,seq having count ( * ) > 1 )
5 、查找表中多余的重复记录（多个字段），不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in ( select peopleId,seq from vitae group by peopleId,seq having
count ( * ) > 1 )
and rowid not in ( select min (rowid) from vitae group by peopleId,seq having count ( * ) > 1 )
(二)
比方说
在A表中存在一个字段“name”，
而且不同记录之间的“name”值有可能会相同，
现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；
Select Name, Count ( * ) From A Group By Name Having Count ( * ) > 1
如果还查性别也相同大则如下:
Select Name,sex, Count ( * ) From A Group By Name,sex Having Count ( * ) > 1
(三)
方法一
declare @max integer , @id integer
declare cur_rows cursor local for select 主字段, count ( * ) from 表名 group by 主字段 having
count ( * ) > ； 1
open cur_rows
fetch cur_rows into @id , @max
while @@fetch_status = 0
begin
select @max = @max - 1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id , @max
end
close cur_rows
set rowcount 0
方法二
有两个意义上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，
二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。
1 、对于第一种重复，比较容易解决，使用
select distinct * from tableName
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。
2 、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下
假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集
select identity ( int , 1 , 1 ) as autoID, * into #Tmp from tableName
select min (autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in ( select autoID from #tmp2)
最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写
在select子句中省去此列）
(四)查询重复
select * from tablename
where id in ( select id from tablename group by id having count (id) > 1 )
