SQL Server获取某年某月某日特定日期的sql语句

      
        　　--
      
      
        "0"表示"1900-01-01"此日期正好为星期一
      
      
        --
      
      
        当前月第一天
      
      
        select
      
      
        DATEADD
      
      (mm,
      
        DATEDIFF
      
      (mm,
      
        0
      
      ,
      
        GETDATE
      
      ()),
      
        0
      
      
        )

    

    
      
      
        --
      
      
        本周星期一
      
      
        select
      
      
        DATEADD
      
      (WK,
      
        DATEDIFF
      
      (WK,
      
        0
      
      ,
      
        GETDATE
      
      ()),
      
        0
      
      
        )

    

    
      
      
        --
      
      
        季度第一天
      
      
        select
      
      
        DATEADD
      
      (QQ,
      
        DATEDIFF
      
      (QQ,
      
        0
      
      ,
      
        GETDATE
      
      ()),
      
        0
      
      
        )

    

    
      
      
        --
      
      
        本年第一天
      
      
        select
      
      
        DATEADD
      
      (YY,
      
        DATEDIFF
      
      (YY,
      
        0
      
      ,
      
        GETDATE
      
      ()),
      
        0
      
      
        )

    

    
      
      
        --
      
      
        当天凌晨
      
      
        select
      
      
        DATEADD
      
      (DD,
      
        DATEDIFF
      
      (DD,
      
        0
      
      ,
      
        GETDATE
      
      ()),
      
        0
      
      
        )

    

    
      
      
        --
      
      
        上月最后一天
      
      
        select
      
      
        DATEADD
      
      (MS,
      
        -
      
      
        3
      
      ,
      
        dateadd
      
      (mm,
      
        DATEDIFF
      
      (mm,
      
        0
      
      ,
      
        GETDATE
      
      ()),
      
        0
      
      
        ))

    

    
      
      
        --
      
      
        去年最后一天
      
      
        select
      
      
        DATEADD
      
      (MS,
      
        -
      
      
        3
      
      ,
      
        dateadd
      
      (YY,
      
        DATEDIFF
      
      (YY,
      
        0
      
      ,
      
        GETDATE
      
      ()),
      
        0
      
      
        ))

    

    
      
      
        --
      
      
        本月最后一天
      
      
        select
      
      
        DATEADD
      
      (MS,
      
        -
      
      
        3
      
      ,
      
        dateadd
      
      (mm,
      
        DATEDIFF
      
      (mm,
      
        0
      
      ,
      
        GETDATE
      
      ())
      
        +
      
      
        1
      
      ,
      
        0
      
      
        ))

    

    
      
      
        --
      
      
        本年最后一天
      
      
        select
      
      
        DATEADD
      
      (MS,
      
        -
      
      
        3
      
      ,
      
        dateadd
      
      (yy,
      
        DATEDIFF
      
      (yy,
      
        0
      
      ,
      
        GETDATE
      
      ())
      
        +
      
      
        1
      
      ,
      
        0
      
      
        ))

    

    
      
      
        --
      
      
        本月的第一个星期一
      
      
        select
      
      
        DATEADD
      
      (wk,
      
        DATEDIFF
      
      (wk,
      
        0
      
      ,
      
        dateadd
      
      (dd,
      
        6
      
      
        -
      
      
        datepart
      
      (
      
        day
      
      ,
      
        getdate
      
      ()),
      
        getdate
      
      ())),
      
        0
      
      
        )

        
      
      
        --
      
      
        获取当前的天数
      
      
        select
      
      
        datepart
      
      (D,
      
        getdate
      
      
        ())

        
      
      
        --
      
      
        找到本月的6号，因为6号正好可以排到星期六（本周最后一天，星期天为某周第一天）
      
      
        select
      
      
        dateadd
      
      (dd,
      
        6
      
      
        -
      
      
        datepart
      
      (
      
        day
      
      ,
      
        getdate
      
      ()),
      
        getdate
      
      
        ())

        
      
      
        --
      
      
        获取相差的周数
      
      
        select
      
      
        DATEDIFF
      
      (wk,
      
        0
      
      ,
      
        dateadd
      
      (dd,
      
        6
      
      
        -
      
      
        datepart
      
      (
      
        day
      
      ,
      
        getdate
      
      ()),
      
        getdate
      
      ()))