Problem A: Guess
Time Limit: 1 Sec Memory Limit: 32 MBDescription
In the television program "Shopping Street" of CCTV-2, two people, A and B are guessing the price of a given item. You are asked to decide whose price is closer to the real price.
Input
There are multiple test cases. The first line of input is an integer T (T <= 20) indicating the number of test cases.
Each case contains three integers in one line: P, PA, PB (0 <= PA, PB, P <= 100, | PA – P | != | PB – P |), indicating the real price, the price A guesses and the price B guesses.
Output
For each case, output "A" or "B" according to whose price is closer to the real price.
Sample Input
4
10 8 7
20 20 19
100 9 50
50 39 60
Sample Output
A
A
B
B
HINT
简单题 直接上代码：
#include<stdio.h>
#include
<
string
.h>
int
main()
{
int
t,a,b,c;
scanf(
"
%d
"
,&
t);
while
(t--
)
{
scanf(
"
%d%d%d
"
,&a,&b,&
c);
b
= (b-a)>
0
?(b-a):(a-
b);
c
= (c-a)>
0
?(c-a):(a-
c);
if
(b>c) printf(
"
B\n
"
);
else
printf(
"
A\n
"
);
}
return
0
;
}
/*
*************************************************************
Problem: 1
User: Hui
Language: C
Result: 正确
Time:0 ms
Memory:964 kb
***************************************************************
*/
